Question:
Based on the following reaction identify alkene A
Based on the following reaction identify alkene A
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Ozonolysis with Zn/H\(_2\)O gives aldehydes/ketones without over-oxidation.
Updated On: Apr 23, 2026
- CH\(_2\)=CH-CH=CH\(_2\)
- CH\(_3\)-CH=CH-CH\(_3\)
- CH\(_3\)-CH\(_2\)-CH=CH\(_2\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Ozonolysis of alkenes gives carbonyl compounds. For dienes, each double bond is cleaved separately.
Step 2: Detailed Explanation:
Products: 2HCHO (formaldehyde) and CHO-CHO (glyoxal).
CH\(_2\)=CH-CH=CH\(_2\) (1,3-butadiene) on ozonolysis:
Terminal CH\(_2\)= gives HCHO; internal CH=CH gives CHO-CHO.
Thus, A = 1,3-butadiene.
Step 3: Final Answer:
Thus, A = CH\(_2\)=CH-CH=CH\(_2\).
Ozonolysis of alkenes gives carbonyl compounds. For dienes, each double bond is cleaved separately.
Step 2: Detailed Explanation:
Products: 2HCHO (formaldehyde) and CHO-CHO (glyoxal).
CH\(_2\)=CH-CH=CH\(_2\) (1,3-butadiene) on ozonolysis:
Terminal CH\(_2\)= gives HCHO; internal CH=CH gives CHO-CHO.
Thus, A = 1,3-butadiene.
Step 3: Final Answer:
Thus, A = CH\(_2\)=CH-CH=CH\(_2\).
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