Question:
\( \text{N}_2 \) gas is liberated when [HCl + NaNO$_2$] reacts with the following compounds;
A. CH$_3$CH$_2$NH$_2$
B. urea
C. CH$_2$CONH$_2$
D. C$_6$H$_5$NH$_2$
\( \text{N}_2 \) gas is liberated when [HCl + NaNO$_2$] reacts with the following compounds;
A. CH$_3$CH$_2$NH$_2$
B. urea
C. CH$_2$CONH$_2$
D. C$_6$H$_5$NH$_2$
A. CH$_3$CH$_2$NH$_2$
B. urea
C. CH$_2$CONH$_2$
D. C$_6$H$_5$NH$_2$
Show Hint
Diazotization reactions with nitrous acid or sodium nitrite liberate nitrogen gas in the presence of amines or urea.
Updated On: Apr 22, 2026
- A, B, C
- B, C, D
- A, C, D
- A, B, D
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Understand the reaction.
When sodium nitrite (\( \text{NaNO}_2 \)) reacts with amines and urea in the presence of hydrochloric acid, nitrogen gas (\( \text{N}_2 \)) is liberated. This is a typical reaction known as the diazotization reaction, which produces nitrogen gas as a byproduct.
Step 2: Analyze the options.
- A. CH$_3$CH$_2$NH$_2$: Ethylamine reacts with sodium nitrite to liberate \( \text{N}_2 \) gas.
- B. Urea: Urea reacts with sodium nitrite to produce \( \text{N}_2 \) gas.
- C. CH$_2$CONH$_2$: Acetamide reacts with sodium nitrite, also liberating \( \text{N}_2 \) gas.
- D. C$_6$H$_5$NH$_2$: Aniline does not react in this manner to produce \( \text{N}_2 \) gas under typical conditions.
Step 3: Conclusion.
The correct answer is (1), as ethylamine, urea, and acetamide all liberate nitrogen gas when reacted with sodium nitrite and hydrochloric acid.
When sodium nitrite (\( \text{NaNO}_2 \)) reacts with amines and urea in the presence of hydrochloric acid, nitrogen gas (\( \text{N}_2 \)) is liberated. This is a typical reaction known as the diazotization reaction, which produces nitrogen gas as a byproduct.
Step 2: Analyze the options.
- A. CH$_3$CH$_2$NH$_2$: Ethylamine reacts with sodium nitrite to liberate \( \text{N}_2 \) gas.
- B. Urea: Urea reacts with sodium nitrite to produce \( \text{N}_2 \) gas.
- C. CH$_2$CONH$_2$: Acetamide reacts with sodium nitrite, also liberating \( \text{N}_2 \) gas.
- D. C$_6$H$_5$NH$_2$: Aniline does not react in this manner to produce \( \text{N}_2 \) gas under typical conditions.
Step 3: Conclusion.
The correct answer is (1), as ethylamine, urea, and acetamide all liberate nitrogen gas when reacted with sodium nitrite and hydrochloric acid.
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