Assertion : Out of Infrared and radio waves, the radio waves show more diffraction effect.
Reason (R): Radio waves have greater frequency than infrared waves.
To evaluate the Assertion and Reason given in the question, let us analyze each statement:
Assertion: Out of Infrared and radio waves, the radio waves show more diffraction effect.
Diffraction is more pronounced when the wavelength of the wave is comparable to or larger than the obstacle or aperture size it encounters. Radio waves have longer wavelengths compared to infrared waves, which allows them to diffract more easily around obstacles. Hence, the Assertion is true.
Reason (R): Radio waves have greater frequency than infrared waves.
The frequency and wavelength of a wave are inversely proportional, as described by the equation:
\(v = fλ\)
where v is the speed of the wave (constant for light waves in a vacuum), f is the frequency, and λ is the wavelength. Radio waves actually have a lower frequency compared to infrared waves. Thus, the Reason is false.
Therefore, the conclusion is that the Assertion is true but the Reason is false.

Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).