Concept:
• Collinear vectors are vectors that are parallel to the same line, meaning one can be expressed as a scalar multiple of the other (\( \vec{b} = \lambda \vec{a} \)).
• The dot product of two vectors is zero if and only if the vectors are perpendicular (orthogonal) to each other, or if at least one of them is a zero vector.
Step 1: Evaluate Assertion (A).
The two vectors given are \( \vec{a} \) and \( -2\vec{a} \).
Let \( \vec{b} = -2\vec{a} \). Here, \( \vec{b} \) is a scalar multiple of \( \vec{a} \) with \( \lambda = -2 \).
Since one vector is a scalar multiple of the other, they are parallel (acting along the same line in opposite directions), which makes them collinear. Therefore, Assertion (A) is true.
Step 2: Evaluate Reason (R).
Let us calculate the dot product given in the reason:
\[
\vec{a} \cdot (-2\vec{a}) = -2(\vec{a} \cdot \vec{a}) = -2|\vec{a}|^2
\]
Since it is given that \( \vec{a} \neq \vec{0} \), its magnitude \( |\vec{a}| > 0 \), meaning \( -2|\vec{a}|^2 \neq 0 \).
Thus, the statement \( \vec{a} \cdot (-2\vec{a}) = 0 \) is completely false.
Conclusion:
Assertion (A) is true, and Reason (R) is false. This matches option (C).