Concept:
To find the solution of the given differential equation, we use the variable-separable method. A general solution contains an arbitrary constant \( C \), while a particular solution is obtained by assigning a specific numerical value to \( C \).
Step 1: Solve the differential equation by separating variables.
The given equation is:
\[
\frac{dy}{dx} = e^{x+y} = e^x \cdot e^y
\]
Separating the variables \( x \) and \( y \) onto opposite sides:
\[
\frac{1}{e^y} \, dy = e^x \, dx \quad \Rightarrow \quad e^{-y} \, dy = e^x \, dx
\]
Step 2: Integrate both sides.
Integrating both sides of the separated equation:
\[
\int e^{-y} \, dy = \int e^x \, dx
\]
\[
-e^{-y} = e^x + C_1
\]
Rearranging the terms to align with the standard equation forms:
\[
e^x + e^{-y} = -C_1
\]
Let \( -C_1 = C \) (where \( C \) is an arbitrary constant):
\[
e^x + e^{-y} = C
\]
This represents the general solution, so Reason (R) is true.
Step 3: Evaluate Assertion (A).
A particular solution is obtained by substituting a specific value for the constant \( C \). If we select \( C = -2 \), the equation becomes:
\[
e^x + e^{-y} = -2
\]
This matches the assertion statement perfectly. Thus, Assertion (A) is true.
Conclusion:
Both statements are true, and the general solution equation directly explains how the particular solution is constructed. Thus, option (A) is the correct choice.