Question:
Angle strain in cyclopropane is ________.
Angle strain in cyclopropane is ________.
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Angle strain in cyclopropane is ____.
Updated On: Apr 15, 2026
- $24^{\circ}44^{\prime}$
- $9^{\circ}44^{\prime}$
- $44^{\prime}$
- $-5^{\circ}16^{\prime}$
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The Correct Option is A
Solution and Explanation
Step 1: Formula
Angle strain ($\alpha$) is calculated using the formula: $\alpha = \frac{1}{2}[109^{\circ}28^{\prime} - \theta]$, where $\theta$ is the bond angle.
Step 2: Analysis
In cyclopropane, the molecule is an equilateral triangle, so the bond angle $\theta = 60^{\circ}$.
Step 3: Calculation
$\alpha = \frac{1}{2}(109^{\circ}28^{\prime} - 60^{\circ}) = \frac{1}{2}(49^{\circ}28^{\prime})$. $\alpha = 24^{\circ}44^{\prime}$.
Final Answer: (A)
Angle strain ($\alpha$) is calculated using the formula: $\alpha = \frac{1}{2}[109^{\circ}28^{\prime} - \theta]$, where $\theta$ is the bond angle.
Step 2: Analysis
In cyclopropane, the molecule is an equilateral triangle, so the bond angle $\theta = 60^{\circ}$.
Step 3: Calculation
$\alpha = \frac{1}{2}(109^{\circ}28^{\prime} - 60^{\circ}) = \frac{1}{2}(49^{\circ}28^{\prime})$. $\alpha = 24^{\circ}44^{\prime}$.
Final Answer: (A)
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