Question:

An observer is standing below a freely falling source of sound of frequency 900 Hz. The change in the frequency noticed by the observer after 3 seconds of free fall of the source is (speed of sound in air is 330 ms\(^{-1}\) and acceleration due to gravity = 10 ms\(^{-2}\))

Show Hint

The time interval between maxima and minima in a beat pattern is half the beat period.
Updated On: May 5, 2026
  • 990 Hz
     

  • 818.18 Hz
     

  • 81.82 Hz
     

  • 90 Hz

Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Step 1: Understanding Beat Phenomenon
- When two waves of close frequencies superpose, they produce beats due to interference.
- The beat frequency is given by: \[ f_{\text{beat}} = |f_1 - f_2| \]
- Here, \( f_1 = 128 \, \text{Hz} \), \( f_2 = 124 \, \text{Hz} \). Step 2: Maximum to Minimum Intensity
- One beat cycle consists of one maximum and one minimum.
- Time from maximum to adjacent minimum = half of beat period.
- Beat frequency: \[ f_{\text{beat}} = 128 - 124 = 4 \, \text{Hz} \]
- Beat period: \[ T_{\text{beat}} = \frac{1}{4} \, \text{s} \]
- Required time: \[ \Delta t = \frac{T_{\text{beat}}}{2} = \frac{1}{8} \, \text{s} \] Step 3: Final Answer
- Time between maximum and adjacent minimum intensity = \( \frac{1}{8} \, \text{s} \)
Was this answer helpful?
0
0

Top TS EAMCET Physics Questions

View More Questions