To find the kinetic energy (KE) of the object at time \( t = 5 \, \text{s} \), we first need to determine its velocity at that time.
Given:
- Initial velocity (\( v_0 \)) = \( 5 \, \text{m/s} \)
- Acceleration (\( a \)) = \( 1 \, \text{m/s}^2 \)
- Time (\( t \)) = \( 5 \, \text{s} \)
The velocity at any time \( t \) can be found using the equation of motion:
\[ v = v_0 + at \]
Substituting the given values:
\[ v = 5 \, \text{m/s} + (1 \, \text{m/s}^2 \times 5 \, \text{s}) \]
\[ v = 5 \, \text{m/s} + 5 \, \text{m/s} \]
\[ v = 10 \, \text{m/s} \]
Now, we can calculate the kinetic energy at \( t = 5 \, \text{s} \). The kinetic energy (KE) is given by:
\[ KE = \frac{1}{2} m v^2 \]
where \( m \) is the mass of the object. Substituting the given mass (\( m = 1 \, \text{kg} \)) and the calculated velocity (\( v = 10 \, \text{m/s} \)):
\[ KE = \frac{1}{2} \times 1 \, \text{kg} \times (10 \, \text{m/s})^2 \]
\[ KE = \frac{1}{2} \times 1 \times 100 \]
\[ KE = 50 \, \text{J} \]
Therefore, the kinetic energy of the object at time \( t = 5 \, \text{s} \) is \( 50 \, \text{J} \).
Thus Correct Answer is Option 4(D):\(50J\)
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
Kinetic energy of an object is the measure of the work it does as a result of its motion. Kinetic energy is the type of energy that an object or particle has as a result of its movement. When an object is subjected to a net force, it accelerates and gains kinetic energy as a result. Kinetic energy is a property of a moving object or particle defined by both its mass and its velocity. Any combination of motions is possible, including translation (moving along a route from one spot to another), rotation around an axis, vibration, and any combination of motions.
