An ellipse has OB as semi-minor axis, \( F \) and \( F' \) its foci and the angle \( \angle \text{FBF'} \) is a right angle. Then the eccentricity of the ellipse is
Show Hint
For an ellipse with a right angle between the foci and any point, the eccentricity can be found using the relation \( e = \frac{1}{\sqrt{2}} \).
Step 1: Use the geometric property of ellipses.
For an ellipse, if the angle between the line joining a point on the ellipse and the two foci is 90°, then the eccentricity \( e \) is \( \frac{1}{\sqrt{2}} \).
Step 2: Conclusion.
The eccentricity of the ellipse is \( \frac{1}{\sqrt{2}} \).
Final Answer:
\[
\boxed{\frac{1}{\sqrt{2}}}
\]