Question:

An ellipse has OB as semi-minor axis, \( F \) and \( F' \) its foci and the angle \( \angle \text{FBF'} \) is a right angle. Then the eccentricity of the ellipse is

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For an ellipse with a right angle between the foci and any point, the eccentricity can be found using the relation \( e = \frac{1}{\sqrt{2}} \).
Updated On: Mar 25, 2026
  • \( \frac{1}{\sqrt{2}} \)
  • \( \frac{1}{2} \)
  • \( \frac{1}{4} \)
  • \( \frac{1}{\sqrt{3}} \)
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The Correct Option is A

Solution and Explanation


Step 1: Use the geometric property of ellipses.

For an ellipse, if the angle between the line joining a point on the ellipse and the two foci is 90°, then the eccentricity \( e \) is \( \frac{1}{\sqrt{2}} \).
Step 2: Conclusion.

The eccentricity of the ellipse is \( \frac{1}{\sqrt{2}} \). Final Answer: \[ \boxed{\frac{1}{\sqrt{2}}} \]
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