Question:
The equation of the ellipse with focus at (±5,0) and eccentricity =(5)/(6) is:
The equation of the ellipse with focus at (±5,0) and eccentricity =(5)/(6) is:
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For ellipse: b²=a²(1-e²).
Updated On: Mar 18, 2026
- (x²)/(36)+(y²)/(25)=1
- (x²)/(36)+(y²)/(11)=1
- (x²)/(25)+(y²)/(11)=1
- None of these
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Relation. e=(c)/(a)=(5)/(6) a=6
Step 2: Compute b². b²=a²-c²=36-25=11
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