Step 1: XeO3F2: AX5E0, 0 lone pairs.
Step 2: ICl2-: 8 valence electrons on I, 2 bonds use 2, leaving 3 lone pairs.
Step 3: ClO-: 8 valence electrons on Cl, 1 bond uses 1, leaving 3 lone pairs.
Step 4: SO3(2-): AX3E1, only 1 lone pair.
Step 5: 2 species (ICl2-, ClO-) have exactly 3 lone pairs.
\[\boxed{(D)\ 2}\]