Question:

Aldehydes and Ketones can be converted to alkanes using
(A). LiAlH\({}_{4}\)/ H\({}_{3}\)O\({}^{+}\)
(B). Zn-Hg/ conc\({}^{n}\) HCl
(C). NH\({}_{2}\)-NH\({}_{2}\) / KOH in ethylene glycol
(D). K\({}_{2}\)Cr\({}_{2}\)O\({}_{7}\)/ dil.H\({}_{2}\)SO\({}_{4}\)

Show Hint

Clemmensen and Wolff-Kishner reductions remove the carbonyl oxygen completely.
Updated On: Nov 12, 2026
  • (A), (B) and (D) only.
  • (A) and (C) only.
  • (B) and (C) only.
  • (A), (C) and (D) only.
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
Converting C=O into \(\text{CH}_2\) needs complete removal of the oxygen.

Step 2: Check Each Reagent
(A) \(\text{LiAlH}_4\) gives only alcohols. (B) Zn-Hg with conc. HCl is the Clemmensen reduction and gives alkanes. (C) \(\text{NH}_2\text{NH}_2\) with KOH in ethylene glycol is the Wolff-Kishner reduction and gives alkanes.

Step 3: Reagent D
(D) Acidified \(\text{K}_2\text{Cr}_2\text{O}_7\) is an oxidising agent, so it does not reduce the carbonyl group.

Step 4: Result
Only (B) and (C) convert aldehydes and ketones to alkanes.

Final Answer:
Only (B) and (C) give alkanes. \[ \boxed{\text{(C) }\text{(B) and (C) only}} \]
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