Question:

After striking the floor a certain ball rebounds (4)/(5)th of its height from which it has fallen. The total distance that the ball travels before coming to rest if it is gently released from a height of 120 m is

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For repeated rebounds, total distance =h(1+r)/(1-r).
Updated On: Mar 20, 2026
  • \(960\text{ m}\)
  • \(1000\text{ m}\)
  • \(1080\text{ m}\)
  • Infinite
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The Correct Option is C

Solution and Explanation


Step 1:
Let initial height h=120 m and rebound ratio r=\frac45.
Step 2:
Total distance travelled: S=h((1+r)/(1-r))
Step 3:
S=120((1+\frac45)/(1-\frac45)) =120((9/5)/(1/5))=120×9=1080 m
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