After striking the floor a certain ball rebounds (4)/(5)th of its height from which it has fallen. The total distance that the ball travels before coming to rest if it is gently released from a height of 120 m is
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For repeated rebounds, total distance =h(1+r)/(1-r).
Step 1: Let initial height h=120 m and rebound ratio r=\frac45.
Step 2: Total distance travelled:
S=h((1+r)/(1-r))
Step 3:
S=120((1+\frac45)/(1-\frac45))
=120((9/5)/(1/5))=120×9=1080 m