According to recent research, air turbulence has increased in various regions around the world due to climate change. Turbulence makes flights bumpy and often delays the flights.
Assume that an airplane observes severe turbulence, moderate turbulence or light turbulence with equal probabilities. Further, the chance of an airplane reaching late to the destination are 55\%, 37\% and 17\% due to severe, moderate and light turbulence respectively.
On the basis of the above information, answer the following questions:
Find the probability that an airplane reached its destination late. If the airplane reached its destination late, find the probability that it was due to moderate turbulence.
Step 1: Given Information. Turbulence can be severe, moderate, or light, each occurring with equal probabilities: \[ P(\text{Severe}) = P(\text{Moderate}) = P(\text{Light}) = \frac{1}{3}. \] The probability of an airplane reaching late due to: \[ P(\text{Late}|\text{Severe}) = 0.55, \quad P(\text{Late}|\text{Moderate}) = 0.37, \quad P(\text{Late}|\text{Light}) = 0.17. \].
Step 2: Find the probability that an airplane reached its destination late. Using the law of total probability: \[ P(\text{Late}) = P(\text{Late}|\text{Severe})P(\text{Severe}) + P(\text{Late}|\text{Moderate})P(\text{Moderate}) + P(\text{Late}|\text{Light})P(\text{Light}) \] Substituting the values: \[ P(\text{Late}) = (0.55 \cdot \frac{1}{3}) + (0.37 \cdot \frac{1}{3}) + (0.17 \cdot \frac{1}{3}) \] Simplifying: \[ P(\text{Late}) = \frac{0.55 + 0.37 + 0.17}{3} = \frac{1.09}{3} = 0.3633. \]
Step 3: Find the probability that it was due to moderate turbulence. Using Bayes' theorem: \[ P(\text{Moderate}|\text{Late}) = \frac{P(\text{Late}|\text{Moderate})P(\text{Moderate})}{P(\text{Late})} \] Substituting the values: \[ P(\text{Moderate}|\text{Late}) = \frac{(0.37 \cdot \frac{1}{3})}{0.3633} \] \[ P(\text{Moderate}|\text{Late}) = \frac{0.37}{3 \cdot 0.3633} = \frac{0.37}{1.09} = 0.3394. \]
Final Answers: The probability that an airplane reached its destination late is: \[ P(\text{Late}) = 0.3633. \] The probability that the airplane was late due to moderate turbulence is: \[ P(\text{Moderate}|\text{Late}) = 0.3394. \]
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Airplanes are by far the safest mode of transportation when the number of transported passengers is measured against personal injuries and fatality totals. Previous records state that the probability of an airplane crash is \( 0.00001\% \). Further, there are 95% chances that there will be survivors after a plane crash. Assume that in case of no crash, all travellers survive. Let \( E_1 \) be the event that there is a plane crash and \( E_2 \) be the event that there is no crash. Let \( A \) be the event that passengers survive after the journey. On the basis of the above information, answer the following questions:
(i) Find the probability that the airplane will not crash.
(ii) Find \( P(A \,|\, E_1) + P(A \,|\, E_2) \).
(iii)
(a) Find \( P(A) \).
OR
(b) Find \( P(E_2 \,|\, A) \).