Question:
A wheat crop growing in a 40-hectare area was irrigated with 10 cumecs of water for 6 hours. Water stored in the root zone was 30 cm. What is the field application efficiency?
A wheat crop growing in a 40-hectare area was irrigated with 10 cumecs of water for 6 hours. Water stored in the root zone was 30 cm. What is the field application efficiency?
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Field application efficiency:
- Efficiency = (Water stored Water applied) × 100.
- Losses: Runoff, deep percolation, evaporation.
- Efficiency = (Water stored Water applied) × 100.
- Losses: Runoff, deep percolation, evaporation.
Updated On: Aug 27, 2026
- 20.55%
- 44.44%
- 50.35%
- 55.55%
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Question:
This question tests the calculation of field application efficiency.
Step 2: Key Formula or Approach:
Field application efficiency = (Water stored in root zone Water applied) × 100.
Water applied = Discharge × Time.
Water stored = Depth of water stored × Area.
Step 3: Detailed Explanation:
Given:
Area = 40 ha = 40 × 10,000 = 4,00,000 m².
Discharge = 10 cumecs = 10 m³/s.
Time = 6 hours = 6 × 3600 = 21,600 s.
Water applied = 10 × 21,600 = 2,16,000 m³.
Water stored = 30 cm = 0.3 m.
Volume of water stored = 0.3 × 4,00,000 = 1,20,000 m³.
Field application efficiency = (1,20,000 2,16,000) × 100 = 55.55%.
Final Answer:
Thus, the field application efficiency is 55.55%, which corresponds to option (D).
[0.5cm]
This question tests the calculation of field application efficiency.
Step 2: Key Formula or Approach:
Field application efficiency = (Water stored in root zone Water applied) × 100.
Water applied = Discharge × Time.
Water stored = Depth of water stored × Area.
Step 3: Detailed Explanation:
Given:
Area = 40 ha = 40 × 10,000 = 4,00,000 m².
Discharge = 10 cumecs = 10 m³/s.
Time = 6 hours = 6 × 3600 = 21,600 s.
Water applied = 10 × 21,600 = 2,16,000 m³.
Water stored = 30 cm = 0.3 m.
Volume of water stored = 0.3 × 4,00,000 = 1,20,000 m³.
Field application efficiency = (1,20,000 2,16,000) × 100 = 55.55%.
Final Answer:
Thus, the field application efficiency is 55.55%, which corresponds to option (D).
[0.5cm]
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