Step 1: Understanding the Concept:
"Cumec" is a unit of volumetric flow rate (cubic meters per second, \(m^3/s\)).
A "cumec-day" is a unit of volume representing the total volume of water discharged by a flow of one cumec over a period of one full day (24 hours).
Step 2: Key Formula or Approach:
Convert flow rate and time to total volume:
\[ \text{Volume} = \text{Flow Rate} \times \text{Time} \]
\[ 1 \text{ hectare (ha)} = 10,000 \text{ m}^2 \]
Step 3: Detailed Explanation:
Let's calculate the volume of 1 cumec-day:
\[ 1 \text{ cumec-day} = 1 \text{ m}^3/\text{s} \times 24 \text{ hours} \]
\[ 1 \text{ cumec-day} = 1 \text{ m}^3/\text{s} \times 24 \times 3600 \text{ seconds} \]
\[ 1 \text{ cumec-day} = 86,400 \text{ m}^3 \]
Now, express this volume in hectare-meters (ha-m):
\[ 1 \text{ ha-m} = 1 \text{ ha} \times 1 \text{ m} = 10,000 \text{ m}^2 \times 1 \text{ m} = 10,000 \text{ m}^3 \]
\[ \text{Volume in ha-m} = \frac{86,400 \text{ m}^3}{10,000 \text{ m}^3/\text{ha-m}} = 8.64 \text{ ha-m} \]
Step 4: Final Answer:
One cumec day is equal to 8.64 ha-m, corresponding to option (B).