The magnification \( m \) produced by a mirror is given by the formula: \[ m = - \frac{v}{u} \] Where:
\( v \) is the image distance,
\( u \) is the object distance.
Given that the image is real and enlarged, the image distance is positive, and the object distance is negative. The condition that the image just touches the pencil means the image and object distances add up to the focal length. Therefore: \[ v + u = f \] Also, the relationship between the focal length \( f \), object distance \( u \), and image distance \( v \) for a mirror is given by the mirror equation: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] From these two equations, we can calculate the magnification produced by the mirror.
Two charges \( +q \) and \( -q \) are placed at points \( A \) and \( B \) respectively which are at a distance \( 2L \) apart. \( C \) is the midpoint of \( AB \). The work done in moving a charge \( +Q \) along the semicircle CSD (\( W_1 \)) and along the line CBD (\( W_2 \)) are 
Find work done in bringing charge q = 3nC from infinity to point A as shown in the figure : 
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).