Step 1: Recall rotational kinematics formula.
For angular motion with constant angular acceleration:
\[
\theta = \omega_0 t + \frac{1}{2}\alpha t^2
\]
Step 2: Identify the given values.
Initial angular velocity:
\[
\omega_0 = 4 \, \text{rad/s}
\]
Angular acceleration:
\[
\alpha = 2 \, \text{rad/s}^2
\]
Time:
\[
t = 4 \, s
\]
Step 3: Substitute into the formula.
\[
\theta = (4)(4) + \frac{1}{2}(2)(4^2)
\]
Step 4: Simplify each term.
First term:
\[
4 \times 4 = 16
\]
Second term:
\[
\frac{1}{2} \times 2 \times 16 = 16
\]
Step 5: Add both contributions.
\[
\theta = 16 + 16 = 32
\]
Step 6: Interpret physically.
The total angular displacement consists of contribution due to initial velocity and due to acceleration.
Step 7: Final conclusion.
Hence, the angle turned is:
\[
\boxed{32 \, \text{radians}}
\]
Therefore, the correct option is
\[
\boxed{(1)\ 32}
\]