Question:

A moving coil galvanometer has resistance \(50\ \Omega\) and it indicates full deflection at 4 mA current. A voltmeter is made using this galvanometer and a \(5\ \mathrm{k\Omega}\) resistance. The maximum voltage, that can be measured using this voltmeter, will be close to :

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A voltmeter is a galvanometer in series with a large resistance; the maximum voltage is \(I_g(G + R)\).
Updated On: Nov 5, 2026
  • \(15\) V
  • \(10\) V
  • \(40\) V
  • \(20\) V
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The Correct Option is D

Solution and Explanation

The series resistance is \(R = 5\ \mathrm{k\Omega} = 5000\ \Omega\) and \(G = 50\ \Omega\), so the total resistance is \(5050\ \Omega\).
Maximum voltage \(V = I_g(G + R) = 4 \times 10^{-3} \times 5050 = 20.2\) V \(\approx 20\) V.
Answer: (4) \(20\) V
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