Question:
A man at a distance \(11\,km\) from two pillars wants to see them separately. What will be the approximate distance between the pillars?
A man at a distance \(11\,km\) from two pillars wants to see them separately. What will be the approximate distance between the pillars?
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Minimum resolvable distance \(d = \theta D\); use \(\theta \approx 3 \times 10^{-4}\,rad\) for human eye.
Updated On: Apr 16, 2026
- \(3\,m\)
- \(1\,m\)
- \(0.25\,m\)
- \(0.5\,m\)
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The Correct Option is A
Solution and Explanation
Concept: Resolving power of human eye
\[
\theta \approx 1' = \frac{1}{60}^\circ \approx 3 \times 10^{-4}\, \text{rad}
\]
Step 1: Use small angle formula \[ \theta = \frac{d}{D} \]
Step 2: Substitute values \[ d = \theta D = (3 \times 10^{-4})(11 \times 10^3) = 3\,m \]
Step 1: Use small angle formula \[ \theta = \frac{d}{D} \]
Step 2: Substitute values \[ d = \theta D = (3 \times 10^{-4})(11 \times 10^3) = 3\,m \]
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