Question:

A given charge \( Q \) is divided into two parts which are then kept at a distance \( d \) apart. The electrostatic force between them will be maximum if the two parts are

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Product \( x(Q-x) \) is maximum when both are equal.
Updated On: Apr 21, 2026
  • \( \frac{Q}{4} \) and \( \frac{3Q}{4} \)
  • \( \frac{7Q}{8} \) and \( \frac{Q}{8} \)
  • \( \frac{Q}{3} \) and \( \frac{2Q}{3} \)
  • \( \frac{5Q}{6} \) and \( \frac{Q}{6} \)
  • \( \frac{Q}{2} \) each
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The Correct Option is

Solution and Explanation

Concept: \[ F \propto q_1 q_2 \]

Step 1:
Let charges be \( x \) and \( Q-x \).
\[ F \propto x(Q-x) \]

Step 2:
Maximize.
Maximum when: \[ x = \frac{Q}{2} \]
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