Question:
A galvanometer has resistance G and range Vg. How much resistance is required to read voltage up to V volt?
A galvanometer has resistance G and range Vg. How much resistance is required to read voltage up to V volt?
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The total resistance must give full-scale current at voltage V.
Updated On: Oct 1, 2026
- \(GV_g\)
- \(G(\frac{V-V_g}{V})\)
- \(G(\frac{V}{V_g}-1)\)
- \(G(\frac{V+V_g}{V})\)
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The Correct Option is C
Solution and Explanation
Step 1: Full-scale current
The galvanometer gives full deflection at current \(I_g = \frac{V_g}{G}\).
Step 2: Series resistance
For range \(V\): \(I_g(G+R) = V\), so \(G + R = \frac{VG}{V_g}\).
Step 3: Solve
\[ R = G\left(\frac{V}{V_g} - 1\right) \]
Option (C).
Final Answer:
The required resistance is G(V/Vg - 1). \[ \boxed{\text{(C)}\ G\left(\frac{V}{V_g}-1\right)} \]
The galvanometer gives full deflection at current \(I_g = \frac{V_g}{G}\).
Step 2: Series resistance
For range \(V\): \(I_g(G+R) = V\), so \(G + R = \frac{VG}{V_g}\).
Step 3: Solve
\[ R = G\left(\frac{V}{V_g} - 1\right) \]
Option (C).
Final Answer:
The required resistance is G(V/Vg - 1). \[ \boxed{\text{(C)}\ G\left(\frac{V}{V_g}-1\right)} \]
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