Question:

An ammeter has resistance \(R\) and range \(I\). What resistance should be connected in parallel with it to increase its range by \(nI\)?

Show Hint

The ammeter and shunt are in parallel, so they have equal potential difference. The shunt carries the extra current nI.
Updated On: Nov 12, 2026
  • \(\frac{R}{(n-1)}\)
  • \(\frac{R}{(n+1)}\)
  • \(\frac{R}{n}\)
  • \(Rn\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
A shunt is connected in parallel so that the extra current bypasses the ammeter.

Step 2: Currents
The ammeter carries its full range \(I\) and the shunt carries the extra current \(nI\).

Step 3: Equal Potential Difference
\(IR=(nI)S\).

Step 4: Solve
\(S=\dfrac{R}{n}\).

Final Answer:
The required shunt resistance is R over n. \[ \boxed{\text{(C) }\dfrac{R}{n}} \]
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