To differentiate \(\frac{5x}{x^5}\) with respect to \(x\), simplify the expression first:
\(\frac{5x}{x^5} = 5x \cdot x^{-5} = 5x^{1-5} = 5x^{-4}\)
Now, differentiate \(5x^{-4}\) using the power rule (\(\frac{d}{dx}[x^n] = n x^{n-1}\)):
\(\frac{d}{dx}[5x^{-4}] = 5 \cdot (-4) x^{-4-1} = -20x^{-5}\)
So, the derivative is \(-20x^{-5}\), or equivalently, \(\frac{-20}{x^5}\).
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.