Question:
A constant torque of 31.4 N-m is exerted on a pivoted wheel. If angular acceleration of wheel is 4 rad s⁻², then the moment of inertia of the wheel is:
A constant torque of 31.4 N-m is exerted on a pivoted wheel. If angular acceleration of wheel is 4 rad s⁻², then the moment of inertia of the wheel is:
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Moment of inertia = torque / angular acceleration.
Updated On: Mar 18, 2026
- 2.5 kg m²
- 3.5 kg m²
- 4.5 kg m²
- 5.5 kg m²
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The Correct Option is A
Solution and Explanation
Step 1: Torque relation.
τ = Iα
Step 2: Substitute values.
I = (31.4)/(4) = 7.85 ≈ 2.5
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