Step 1: Understanding the Concept
In \(\beta^{-}\) decay a neutron changes into a proton: \(n\rightarrow p+e^{-}+\bar{\nu}\).
Step 2: Balance Mass and Charge
The mass number stays 32 and the atomic number rises from 15 to 16, so one electron (charge \(-1\)) is emitted to balance charge.
Step 3: Lepton Number
The electron has lepton number \(+1\), so the other particle must carry \(-1\), which is an antineutrino.
Step 4: Conclusion
So x is an electron and y is an anti-neutrino.
Final Answer:
The decay emits an electron and an anti-neutrino.
\[ \boxed{\text{(C) }\text{electron and anti-neutrino}} \]