Question:

A common example of \(\beta ^{-}\) decay is
\({}_{15}\text{P}^{32}\longrightarrow {}_{16}\text{S}^{32}+x+y\)
Then x and y , respectively, stand for

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In beta minus decay a neutron changes to a proton, emitting an electron and an antineutrino.
Updated On: Nov 12, 2026
  • positron and anti - neutrino
  • electron and neutrino
  • electron and anti-neutrino
  • positron and neutrino
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
In \(\beta^{-}\) decay a neutron changes into a proton: \(n\rightarrow p+e^{-}+\bar{\nu}\).

Step 2: Balance Mass and Charge
The mass number stays 32 and the atomic number rises from 15 to 16, so one electron (charge \(-1\)) is emitted to balance charge.

Step 3: Lepton Number
The electron has lepton number \(+1\), so the other particle must carry \(-1\), which is an antineutrino.

Step 4: Conclusion
So x is an electron and y is an anti-neutrino.

Final Answer:
The decay emits an electron and an anti-neutrino. \[ \boxed{\text{(C) }\text{electron and anti-neutrino}} \]
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