The formula for half-life decay is:
\[
N(t) = N_0 \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}}
\]
where:
- \( N(t) \) is the remaining quantity after time \( t \),
- \( N_0 \) is the initial quantity,
- \( T_{1/2} \) is the half-life of the substance.
Given that \( T_{1/2} = 5 \) years and the initial weight is 64 gm, after 15 years:
\[
N(15) = 64 \left( \frac{1}{2} \right)^{\frac{15}{5}} = 64 \left( \frac{1}{2} \right)^3 = 64 \times \frac{1}{8} = 8 \, \text{gm}.
\]
Thus, the remaining weight after 15 years is 8 gm.