Question:

A circular disc A and a ring B have same mass and same radius. If they are rotated with the same angular speed about their own axis, then

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For same mass and radius, ring always has greater moment of inertia than disc.
Updated On: May 8, 2026
  • A has less moment of inertia than B
  • A has less rotational kinetic energy than B
  • A and B have the same angular momentum
  • A has greater angular momentum than B
  • A has the same moment of inertia as that of B
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The Correct Option is A

Solution and Explanation

Concept: Moment of inertia: \[ I_{disc} = \frac{1}{2}mR^2, \quad I_{ring} = mR^2 \]

Step 1:
Compare moment of inertia. \[ I_{disc} < I_{ring} \]

Step 2:
Rotational kinetic energy. \[ K = \frac{1}{2}I\omega^2 \Rightarrow K_{disc} < K_{ring} \]

Step 3:
Angular momentum. \[ L = I\omega \Rightarrow L_{disc} < L_{ring} \]

Step 4:
Conclusion. Options (A) and (B) are correct.
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