Question:
A ball moves in a circle of radius $0.5\ \text{m}$ from A to B (quarter circle) in $\sqrt{2}\ \text{s}$. The average velocity is:
A ball moves in a circle of radius $0.5\ \text{m}$ from A to B (quarter circle) in $\sqrt{2}\ \text{s}$. The average velocity is:
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Displacement is the straight-line distance between the start and end points, not the curved path length.
Updated On: Apr 28, 2026
- 0.25
- 0.5
- 0.75
- 1.5
- 1.25
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Average Velocity $= \frac{\text{Displacement}}{\text{Time}}$.
Step 2: Analysis
For a quarter circle from $(0, r)$ to $(r, 0)$, the displacement is the chord length: $d = \sqrt{r^2 + r^2} = r\sqrt{2}$. Given $r = 0.5\ m$, Displacement $= 0.5\sqrt{2}\ m$.
Step 3: Calculation
Average Velocity $= \frac{0.5\sqrt{2}}{\sqrt{2}} = 0.5\ ms^{-1}$. Final Answer: (B)
Average Velocity $= \frac{\text{Displacement}}{\text{Time}}$.
Step 2: Analysis
For a quarter circle from $(0, r)$ to $(r, 0)$, the displacement is the chord length: $d = \sqrt{r^2 + r^2} = r\sqrt{2}$. Given $r = 0.5\ m$, Displacement $= 0.5\sqrt{2}\ m$.
Step 3: Calculation
Average Velocity $= \frac{0.5\sqrt{2}}{\sqrt{2}} = 0.5\ ms^{-1}$. Final Answer: (B)
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