Question

A particle moves in a circular path of radius 4 cm

Hint:

In exam papers, sometimes an overarching data statement is printed as a standalone line before presenting the actual questions that depend on it.
Always look closely at the immediately following questions (like Q23) to apply this extracted data!

Answer 1

Step 1: Understanding the Concept:
This statement strictly provides the geometric boundary condition for a particle undergoing circular motion.
Without additional kinematic variables like time, velocity, or frequency, it acts as a descriptive setup rather than a complete solvable question.
Step 2: Key Formula or Approach:
The foundational property of a circular path is its circumference, defined by the formula $C = 2\pi r$.
This tells us the total path length covered in one single, complete revolution.
Step 3: Detailed Explanation:
The given radius of the circular path is strictly $r = 4\text{ cm}$.
By substituting this radius into the circumference formula, we can determine the distance for one loop:
\[ C = 2\pi(4) = 8\pi\text{ cm} \] Since no further operational data is provided in this specific line, this is the maximum extractable physical information.
Step 4: Final Answer:
The particle follows a path where one revolution equals a distance of $8\pi\text{ cm}$.