Question:

A and B together can do a piece of work in 20 days; B and C together in 15 days; C and A together in 12 days. How long will they take to finish the work, working together?

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In these "A+B, B+C, C+A" problems, the total rate is always half the sum of the individual pairs.
Updated On: May 14, 2026
  • 6 days
  • 8 days
  • 10 days
  • 12 days
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The Correct Option is C

Solution and Explanation


Step 1: Concept

Work rate is the reciprocal of time taken.

Step 2: Analysis

$(A+B)$ rate = $1/20$. $(B+C)$ rate = $1/15$. $(C+A)$ rate = $1/12$.

Step 3: Reasoning

Adding them: $2(A+B+C) = 1/20 + 1/15 + 1/12$.
LCM of 20, 15, 12 is 60.
$2(A+B+C) = (3+4+5)/60 = 12/60 = 1/5$.
$(A+B+C) = 1/10$.

Step 4: Conclusion

Working together, they take the reciprocal of $1/10$, which is 10 days. Final Answer: (C)
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