Capacitance of the capacitor, C = 600 pF
Potential difference, V = 200 V
Electrostatic energy stored in the capacitor is given by,
\(E1=\frac{1}{2} CV^2=\frac{1}{2}X(600×10^-12)×(200)^2 J=1.2×10^{-5}J\)
If supply is disconnected from the capacitor and another capacitor of capacitance C = 600 pF is connected to it, then equivalent capacitance (Ceq) of the combination is given by,
\(\frac{1}{C_eq}=\frac{1}{C}+\frac{1}{C}\)
\(\frac{1}{Ceq} =\frac{1}{600}+\frac{1}{600} = \frac{2}{600}=\frac{1}{300 }= 300 pF\)
New electrostatic energy can be calculated as
\(E2=1/2Ceq V2= \frac{1}{2}×300×(200)^2 J = 0.6 × 10-5 ^J \)
Loss in electrostatic energy = E1 – E2
= 1.2 × 10−5 0.6 × 10-5 J = 0.6 × 10-5 J = 6 × 10-6 J
Therefore, the electrostatic energy lost in the process is 6 × 10-6 J .
Two charges \( +q \) and \( -q \) are placed at points \( A \) and \( B \) respectively which are at a distance \( 2L \) apart. \( C \) is the midpoint of \( AB \). The work done in moving a charge \( +Q \) along the semicircle CSD (\( W_1 \)) and along the line CBD (\( W_2 \)) are 
Find work done in bringing charge q = 3nC from infinity to point A as shown in the figure : 
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).
The potential of a point is defined as the work done per unit charge that results in bringing a charge from infinity to a certain point.
Some major things that we should know about electric potential:
The ability of a capacitor of holding the energy in form of an electric charge is defined as capacitance. Similarly, we can also say that capacitance is the storing ability of capacitors, and the unit in which they are measured is “farads”.
Read More: Electrostatic Potential and Capacitance
Both the Capacitors C1 and C2 can easily get connected in series. When the capacitors are connected in series then the total capacitance that is Ctotal is less than any one of the capacitor’s capacitance.
Both Capacitor C1 and C2 are connected in parallel. When the capacitors are connected parallelly then the total capacitance that is Ctotal is any one of the capacitor’s capacitance.