Question

A 60 kg man standing on a bridge, jumps vertically down onto a 540 kg boat moving in the river below him with a speed of 10 m/s. The change in the speed of the boat is:

• A. 9 m/s
• B. 10 m/s
• C. 1 m/s
• D. 0.9 m/s

Hint:

Momentum is conserved in the absence of external forces.

Answer 1

The Correct Option is C

Step 1: Conservation of Momentum

\[ (m_1 + m_2) v_f = m_2 v_i \] Solving for \( v_f \), we get: \[ \text{Change in speed} = 1 \text{ m/s} \]
Step 3: Conclusion

Thus, Option (3) is correct.