Question:
2 L water heated from \(27^\circ C\) to \(77^\circ C\), power = 160 J/s. Find time.
2 L water heated from \(27^\circ C\) to \(77^\circ C\), power = 160 J/s. Find time.
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Time = heat required power supplied.
Updated On: Apr 23, 2026
- 5 min 40 s
- 14 min 20 s
- 8 min 20 s
- 16 min 10 s
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Heat required
\[ m = 2\,kg,\quad \Delta T = 50^\circ C \] \[ Q = mc\Delta T = 2 \cdot 4200 \cdot 50 = 420000\,J \]
Step 2: Time
\[ t = \frac{Q}{P} = \frac{420000}{160} = 2625s = 8\,min\,20s \]
\[ m = 2\,kg,\quad \Delta T = 50^\circ C \] \[ Q = mc\Delta T = 2 \cdot 4200 \cdot 50 = 420000\,J \]
Step 2: Time
\[ t = \frac{Q}{P} = \frac{420000}{160} = 2625s = 8\,min\,20s \]
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