Integrate the function: \(\frac {1}{\sqrt {1+4x^2}}\)
Solution and Explanation
\(Let\ 2x = t\)
\(∴ 2dx = dt\)
\(⇒ ∫\frac {1}{\sqrt {1+4x^2}} dx\)= \(\frac 12∫\frac {dt}{\sqrt {1+t^2}}\)
=\(\frac 12[log\ |t+\sqrt {t_2+1}|]+C\) \([∫\frac {1}{\sqrt {x^2+a^2}}dt = log\ |x+\sqrt {x^2+a^2}|]\)
=\(\frac 12 \ log\ |2x+\sqrt {4x^2+1}|+C\)
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- R={(x,y): x and y work at same place}
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- R={(x,y): x is wife of y}
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Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
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Concepts Used:
Integrals of Some Particular Functions
There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.
Integrals of Some Particular Functions:
- ∫1/(x2 – a2) dx = (1/2a) log|(x – a)/(x + a)| + C
- ∫1/(a2 – x2) dx = (1/2a) log|(a + x)/(a – x)| + C
- ∫1/(x2 + a2) dx = (1/a) tan-1(x/a) + C
- ∫1/√(x2 – a2) dx = log|x + √(x2 – a2)| + C
- ∫1/√(a2 – x2) dx = sin-1(x/a) + C
- ∫1/√(x2 + a2) dx = log|x + √(x2 + a2)| + C
These are tabulated below along with the meaning of each part.
