If Young’s modulus of elasticity is $Y = \dfrac{2mg l^2}{5b t e}$, where ‘g’ is the acceleration due to gravity, ‘m’ is the mass, ‘l’ is the length, ‘b’ is the breadth, ‘t’ is the thickness and ‘e’ is the elongation, then the value of $k$ is
Two charges +q and -q, each 1 $\mu$C are arranged as shown in the figure. If x = 2 cm and y = 3 cm then potential difference ($V_A - V_B$) is
The de Broglie wavelength of the most energetic photoelectrons emitted from a photosensitive metal of work function \( \phi \), when light of frequency \( \nu \) is incident on it, is \( \lambda \). Then find \( \nu \) in terms of Planck’s constant \( h \), mass of electron \( m \), and other constants.