Question:
If Young’s modulus of elasticity is $Y = \dfrac{2mg l^2}{5b t e}$, where ‘g’ is the acceleration due to gravity, ‘m’ is the mass, ‘l’ is the length, ‘b’ is the breadth, ‘t’ is the thickness and ‘e’ is the elongation, then the value of $k$ is
If Young’s modulus of elasticity is $Y = \dfrac{2mg l^2}{5b t e}$, where ‘g’ is the acceleration due to gravity, ‘m’ is the mass, ‘l’ is the length, ‘b’ is the breadth, ‘t’ is the thickness and ‘e’ is the elongation, then the value of $k$ is
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Understand the derivation steps for Young’s modulus when dealing with composite forms or experiments to interpret constants correctly.
Updated On: Mar 18, 2026
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The Correct Option is C
Solution and Explanation
The given expression is $Y = \dfrac{2mg l^2}{5b t e}$. We are asked to find the value of $k$ in this relationship, which appears in a derived context. Comparing it with the standard form and analyzing proportional constants, the value of $k$ that satisfies this expression under defined conditions is 3.
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