Calculate the standard enthalpy change of following reaction:
$CH_{4(g)} + 2O_{2(g)} \rightarrow CO_{2(g)} + 2H_{2}O_{(l)}$
if $\Delta_{f}H^{\circ}(CH_{4}) = -75~kJ~mol^{-1}$, $\Delta_{f}H^{\circ}(CO_{2}) = -390~kJ~mol^{-1}$, $\Delta_{f}H^{\circ}(H_{2}O) = -286~kJ~mol^{-1}$