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MHT CET 2020
List of top Questions asked in MHT CET- 2020
Evaluate \( \int_0^{\frac{\pi}{2}} \left( e^{\sin x} - e^{\cos x} \right) \, dx \)
MHT CET - 2020
MHT CET
Mathematics
Some Properties of Definite Integrals
If \( y = \tan^{-1} \left( \frac{\sin 2x}{1 + \cos 2x} \right) \), then
\[ \frac{dy}{dx} = \]
MHT CET - 2020
MHT CET
Mathematics
Differentiation
If the radius of a circular blot of oil is increasing at the rate of $2$ cm/min, then the rate of change of its area when its radius is $3$ cm is
MHT CET - 2020
MHT CET
Mathematics
Number System
If the line
\( 6x - y - 4 = 0 \)
touches the curve
\( y^2 = ax^3 + b \)
at the point
(1, 2),
then
\( a + b = \)
MHT CET - 2020
MHT CET
Mathematics
Applications of Derivatives
If \( \dfrac{d^2y}{dx^2} = \sin x + e^x \), \( y(0) = 3 \) and \( \left.\dfrac{dy}{dx}\right|_{x=0} = 4 \), then the equation of the curve is
MHT CET - 2020
MHT CET
Mathematics
Differential equations
An urn contains 4 red and 5 white balls. Two balls are drawn one after the other without replacement. Find the probability that both the balls are red.
MHT CET - 2020
MHT CET
Mathematics
Probability
If
\[ \int \sqrt{x - 1} \left( \frac{x^2 + 1}{x^2} \right) dx = \frac{2}{3} (x - 1)^k + c, \quad \text{then the value of } k \text{ is} \]
MHT CET - 2020
MHT CET
Mathematics
Linear Programming
Evaluate
\[ \int \frac{5^x}{\sqrt{5^{-2x}} - 5^{2x}}\,dx \]
MHT CET - 2020
MHT CET
Mathematics
Integral Calculus
Evaluate the integral:
\[ \int_{-5}^{5} \frac{e^x + e^{-x}}{e^x - e^{-x}} \, dx. \]
MHT CET - 2020
MHT CET
Mathematics
Integral Calculus
Out of 100 people selected at random, 10 have common cold. If five persons are selected at random from the group, then the probability that at most one person will have common cold is
MHT CET - 2020
MHT CET
Mathematics
Probability
The general solution of the differential equation
\[ \sec^2 x \tan y\,dx + \sec^2 y \tan x\,dy = 0 \]
is
MHT CET - 2020
MHT CET
Mathematics
Differential equations
The equation of normal to the curve \( y = \sin \left( \frac{\pi x}{4} \right) \) at the point (2, 5) is
MHT CET - 2020
MHT CET
Mathematics
Trigonometry
If \( f(x) = 2x^2 + bx + c \), \( f(0) = 3 \) and \( f(2) = 1 \), then \( (f \circ f)(1) = \)
MHT CET - 2020
MHT CET
Mathematics
Some Properties of Definite Integrals
If $x^2+y^2=t+\dfrac{1}{t}$ and $x^4+y^4=t^2+\dfrac{1}{t^2}$, then $\dfrac{dy}{dx}=$
MHT CET - 2020
MHT CET
Mathematics
Coordinate Geometry
The area bounded by the parabola \( x^2 = 4y \), the lines \( y = 2 \), \( y = 4 \) and the Y-axis is
MHT CET - 2020
MHT CET
Mathematics
Integral Calculus
The general solution of \( \tan 3x = 1 \) is
MHT CET - 2020
MHT CET
Mathematics
Trigonometry
If \[ A = \begin{bmatrix} 0 & 0 & -1 \\ 0 & -1 & 0 \\ -1 & 0 & 0 \end{bmatrix} \] then
MHT CET - 2020
MHT CET
Mathematics
Matrices
For a sequence if \( S_n = \dfrac{5^n - 2^n}{2^n} \), then its fourth term is
MHT CET - 2020
MHT CET
Mathematics
sequences
If
\[ \sec x + \tan x = 3, \quad x \in \left( 0, \frac{\pi}{2} \right), \]
then
\( \sin x = \)
MHT CET - 2020
MHT CET
Mathematics
Trigonometry
If \( y = \tan^{-1} \left( \frac{x - \sqrt{1 - x^2}}{x + \sqrt{1 - x^2}} \right) \), then \( \frac{dy}{dx} \) is
MHT CET - 2020
MHT CET
Mathematics
Three Dimensional Geometry
If
\[ A = \begin{pmatrix} 2 & 5 \\ 0 & 1 \\ 3 & 0 \end{pmatrix}, \quad A^{-1} = \begin{pmatrix} 3 & -1 \\ -6 & 6 \\ -5 & 2 \end{pmatrix} \]
then the values of \( \alpha \) and \( \beta \) are, respectively
MHT CET - 2020
MHT CET
Mathematics
Matrices
Water at \(100^\circ\text{C}\) cools in 15 minutes to \(75^\circ\text{C}\) in a room temperature of \(25^\circ\text{C}\). Then the temperature of water after 30 minutes is
MHT CET - 2020
MHT CET
Mathematics
Differential equations
If
\[ A = \begin{bmatrix} 2 & -1 \\ -1 & 2 \end{bmatrix}, \]
such that
\[ A^2 - 4A + 3I = 0, \]
then
\( A^{-1} \) is
MHT CET - 2020
MHT CET
Mathematics
Matrices
The coordinates of the point where the line $\dfrac{x-1}{2}=\dfrac{y-2}{-3}=\dfrac{z+3}{4}$ meets the plane $2x+4y-z=1$ are
MHT CET - 2020
MHT CET
Mathematics
Trigonometry
If the lines
\[ \frac{x - 1}{5} = \frac{y + 1}{3} = \frac{3 - z}{\lambda} \quad \text{and} \quad \frac{x + 1}{4} = \frac{1 - 3y}{15} = \frac{z + 1}{1} \]
are perpendicular to each other, then
\( \lambda = \)
MHT CET - 2020
MHT CET
Mathematics
Three Dimensional Geometry
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