Equal moles of NO$_2$(g) and NO(g) are to be placed in a container to produce N$_2$O according to the reaction,
\[
\text{NO}_2 + \text{NO} \rightleftharpoons \text{N}_2\text{O} + \text{O}_2, \quad K_c = 0.914
\]
How many moles of NO$_2$ and NO be placed in the 5.0 L container to have an equilibrium concentration of N$_2$O to be 0.05 M?