Question:
The compound C$_6$H$_5$CH = N – N = CHC$_6$H$_5$ is produced by the reaction of an excess of benzaldehyde with which compound?
The compound C$_6$H$_5$CH = N – N = CHC$_6$H$_5$ is produced by the reaction of an excess of benzaldehyde with which compound?
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Excess aldehyde + hydrazine → azine formation.
Updated On: Apr 23, 2026
- NH$_3$
- NH$_2$NH$_2$
- Hydroxyl amine
- Phenyl hydrazine
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Concept:
Hydrazine reacts with aldehydes to form azines when aldehyde is in excess.
Step 1: Benzaldehyde reacts with NH$_2$NH$_2$ (hydrazine).
Step 2: Two molecules of aldehyde condense with one hydrazine molecule.
Step 3: Product formed: azine (C$_6$H$_5$CH=N–N=CHC$_6$H$_5$).
Conclusion:
Required reagent = Hydrazine
Step 1: Benzaldehyde reacts with NH$_2$NH$_2$ (hydrazine).
Step 2: Two molecules of aldehyde condense with one hydrazine molecule.
Step 3: Product formed: azine (C$_6$H$_5$CH=N–N=CHC$_6$H$_5$).
Conclusion:
Required reagent = Hydrazine
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