Following method of extracting Zn is based on thermodynamics
A: \(2\text{ZnS} + 3\text{O}_2 \rightarrow 2\text{ZnO} + 2\text{SO}_2\)
B: \(\text{ZnO} + \text{C} \rightarrow \text{Zn} + \text{CO}\)
If \(\Delta G_f^{\circ}\) (standard free energies of formation, in kJ mol\(^{-1}\)) of ZnS = -205.4, ZnO = -318.0, SO\(_2\) = -300.4, and CO = -137.3. Free energy changes of the above reaction A and B (respectively) will be: