Question:
Order the species CF$^+$, CF and CF$^-$ according to increasing C–F bond length
Order the species CF$^+$, CF and CF$^-$ according to increasing C–F bond length
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More antibonding electrons $\Rightarrow$ weaker and longer bond.
Updated On: Apr 23, 2026
- CF$^+$ < CF < CF$^-$
- CF$^-$ < CF < CF$^+$
- CF < CF$^-$ < CF$^+$
- CF < CF$^+$ < CF$^-$
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The Correct Option is A
Solution and Explanation
Concept:
Bond length is inversely proportional to bond order. Higher bond order $\Rightarrow$ shorter bond length.
Step 1: Understand effect of charge on bond order:
• CF$^+$: fewer electrons $\Rightarrow$ higher bond order
• CF: intermediate bond order
• CF$^-$: more electrons in antibonding orbitals $\Rightarrow$ lower bond order
Step 2: Relate bond order to bond length:
\[ \text{Higher bond order} \Rightarrow \text{shorter bond} \]
Step 3: Arrange in increasing bond length:
\[ CF^+<CF<CF^- \] Conclusion:
Correct order = CF$^+$ < CF < CF$^-$
Step 1: Understand effect of charge on bond order:
• CF$^+$: fewer electrons $\Rightarrow$ higher bond order
• CF: intermediate bond order
• CF$^-$: more electrons in antibonding orbitals $\Rightarrow$ lower bond order
Step 2: Relate bond order to bond length:
\[ \text{Higher bond order} \Rightarrow \text{shorter bond} \]
Step 3: Arrange in increasing bond length:
\[ CF^+<CF<CF^- \] Conclusion:
Correct order = CF$^+$ < CF < CF$^-$
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