The differential equation dy/dx=√1-y2/y determines a family of circles with
Solve for x, given \( \tan^{-1}\left(\frac{1 - x}{1 + x}\right) = \frac{1}{2} \tan^{-1}(x) \)
If \(1+ (√1+x) tanx = 1+ (√1-x)\) then \(sin4x\) is ?
If x dy= y(dx + ydy), x(1)=1, y(x)>0, then y (-3) is?