If \(P(B) = \frac{3}{5}\), \(P(A/B) = \frac{1}{2}\), and \(P(A \cup B) = \frac{4}{5}\), then \(P(A \cup B)' + P(A')\) is :
\(\int x^x(1 + \log x) \, dx\), \(\text{ is equal to:}\)