\(A \xrightarrow{4KOH,\ O_2} \underset{(\mathrm{Green})}{2B} + 2H_2O\)
\(3B \xrightarrow{4HCl} \underset{(\mathrm{Purple})}{2C} + MnO_2 + 2H_2O\)
\(2C \xrightarrow{H_2O.KI} \underset{(\mathrm{Purple})}{2A} + 2KOH + D\)
In the above sequence of reactions, A and D, respectively, are :