25 ml of the given HCl solution requires 30 mL of 0.1 M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30 mL of 0.2 M aqueous NaOH solutions ?
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- 50 mL
- 12.5 mL
- 25 mL
- 75 mL
The Correct Option is C
Solution and Explanation
Moles of Na2CO3 = 30 mL \(\times\) 0.1 M = 3 mmol, so HCl in 25 mL = 6 mmol.
Molarity of HCl = 6/25 = 0.24 M.
NaOH + HCl \(\rightarrow\) NaCl + H2O. Moles of NaOH = 30 \(\times\) 0.2 = 6 mmol, requiring 6 mmol HCl.
Volume of HCl = 6/0.24 = 25 mL.
Answer: (3) 25 mL
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