A compound 'X' on treatment with \(\mathrm{Br_2/NaOH}\), provided \(\mathrm{C_3H_9N}\), which gives positive carbylamine test. Compound 'X' is :
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- \(\mathrm{CH_3CH_2CH_2CONH_2}\)
- \(\mathrm{CH_3CON(CH_3)_2}\)
- \(\mathrm{CH_3CH_2COCH_2NH}\)
- \(\mathrm{CH_3COCH_2NHCH_3}\)
The Correct Option is A
Solution and Explanation
Hofmann bromamide reaction: \(\mathrm{RCONH_2 + Br_2 + 4NaOH \rightarrow RNH_2 + Na_2CO_3 + 2NaBr + 2H_2O}\), losing one carbon.
So X has four carbons: \(\mathrm{CH_3CH_2CH_2CONH_2}\) (butanamide).
Answer: (1) \(\mathrm{CH_3CH_2CH_2CONH_2}\)
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