The coordination number of Th in \(\mathrm{K_4[Th(C_2O_4)_4(OH_2)_2]}\) is :
\(\left(\mathrm{C_2O_4^{2-}} = \text{Oxalato}\right)\)
\(\left(\mathrm{C_2O_4^{2-}} = \text{Oxalato}\right)\)
Show Hint
- 14
- 10
- 8
- 6
The Correct Option is B
Solution and Explanation
4 oxalate ions, each bidentate: 4 x 2 = 8 donor atoms.
2 water molecules, each monodentate: 2 x 1 = 2 donor atoms.
Coordination number of Th = 8 + 2 = 10.
Answer: (2) 10
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