List of practice Questions

DEF, DEF₂, DE₂F₂, _ _ _ _
Statements: Raman is always successful. No fool is always successful. Conclusions: I. Raman is a fool. II. Raman is not a fool.
Statements: Some desks are caps. No cap is red. Conclusions: I. Some caps are desks. II. No desk is red.
Read the sentence to find out whether there is any grammatical error in it.
Read the sentence to find out whether there is any grammatical error in it.
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series. 3,4,7,7,13,13,21,22,31,34,?
According to the author countrymen should
The proper sequence should be:
The proper sequence should be:
The miser gazed …… at the pile of gold coins in front of him.
I saw a …… of cows in the field.
Read the sentence to find out whether there is any grammatical error in it.
EMBEZZLE
ARROGANT
According to the author, ‘Mentality’ of a nation is mainly product of its
The need for greater understanding between nations
The character of a nation is the result of its
Electrolysis is carried out in three cells:
The equilibrium constant for the disproportionation reaction 2Cu⁺(aq) rightleftharpoons Cu(s) + Cu²+(aq) at 25^∘C (EᶜircCᵤ⁺/Cᵤ=0.52V, EᶜircCᵤ²+/Cᵤ⁺=0.16V) is:
The non-stoichiometric compound Fe₀.94O is formed when x% of Fe²+ ions are replaced by as many (2)/(3)Fe³+ ions. The value of x is:
Al (at. wt. 27) crystallizes in the cubic system with a cell edge of 4.05AA. Its density is 2.7g cm⁻3. Determine the atom unit cell type and calculate the radius of the Al atom.
A compound of Xe and F is found to have 53.5% of Xe. What is the oxidation number of Xe in this compound?
Given the following data: l r Reaction & Energy change (kJ)
Li(s)→ Li(g) & 161
Li(g)→ Li⁺(g) & 520
(1)/(2)F₂(g)→ F(g) & 77
F(g)+e⁻→ F⁻(g) & x
Li⁺(g)+F⁻(g)→ LiF(s) & -1047
Li(s)+(1)/(2)F₂(g)→ LiF(s) & -617 Based on the data provided, the value of electron gain enthalpy of fluorine would be:
The percentage hydrolysis of 0.15M solution of ammonium acetate, Kₐ for CH₃COOH=1.8×10⁻5 and Kb for NH₃=1.8×10⁻5 is:
For a sparingly soluble salt ApBq, the relationship of its solubility product Kₛp with its solubility S is: